The gemara makes it clear that there is a positive mitzva of giluach at the end of the nezirus (and if one would become tamei after the korban before the giluach, they are mevatel this mitzvah of being migaleiach b'tahara). The Tosafos 13a explains the mishna 13b, that if one accepted nezirus for the birth of his son and then nezirus on himself, and after doing 20 days of his own nezirus the son is born, he must interupt his nezirus to keep 30 days for the acceptance on his son and then be mashlim the nezirus with another 10 days. However, if he would do giluach when the nezirus of his son ends, he will only have a 10 day growth when it comes time for his giluach, he should not do any giluach until the end of both nezirus and then do one giluach for both nezirus. Why is this not a problem of doing mitzvos chavilos chavilos (in bundles)?
R' Moshe (o.c. 1:189) doesn't discuss this case, but says a yesod that answers this question. Chavilos is only a problem when one is pushing together multiple actions to get them done more efficiently such as unrelated brachos that should each require a cup of wine being made on one cup. But when one does one ma'aseh mitzvah, but has 2 kiyumim that are fulfilled with that, there is not problem of chavilos. He writes that if one would do kisuy hadam on the blood of many chickens at once, it is not called chavilos since he is doing one ma'aseh mitzvah, just that he is fulfilling many mitzvos through that action. Here too, he is doing one ma'aseh mitzvah of giluach, just that he is fulfilling 2 mitzvos with that action.
This gemara seems to be a pretty good proof to R' Moshe's yesod.
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